Since they are both equal to y, that means that:

3x+4=x-2

2x+4 = -2

2x = -6

x = -3 and plugging -3 into y=x-2 we get y=-3-2 or y=-5 so the point of intersection is (-3,-5)

Let's check our answer by plugging those x and y values into our original two equations.

(-5)=3(-3) + 4 and (-5)=(-3) - 2

-5 = -9 +4 and -5 = -5 Well, those are both true so we have found the point that satisfies both equations.

2. Find the two points where y=|x-4| and y=2/3 x - 2 intersect. Leave the coordinates as impro

per fractions or integers.

Either y = x-4 or y= -x + 4 Now let's plug in 2/3 x - 2 for y in each of the two equations.

2/3 x - 2 = x-4 or 2/3 x - 2 = -x +4

-2 = 1/3 x -4 or 5/3 x - 2 = 4

2 = 1/3 x or 5/3 x= 6

6 = x or x= 18/5 Now let's y=2/3x -2 to figure out the y value.

y = 2/3(6) - 2 and y=2/3(18/5) - 2

y = 4 - 2 and y = 36/15 - 2

y = 2 and y = 12/5 -10/5

and y = 2/5

The two points are (6,2) and (18/5,2/5)

3.Write as a trinomial in descending order: (2x+7) (9x-4)

18x

^{2}- 8x + 63x -28 = 18x

^{2}+ 55x -28

4. (x

^{2}- 4)/(x + 2)

There is no x term in the numerator so the coefficient is zero. So the question is what two numbers add to zero and multiply to negative four? Ans. 2 and -2.

Hence simplify to ((x+2)(x-2))/(x+2) = x-2 =c

5. What is the length of the diagonal of a square of side length 2√15 m, in simplified radical form. Use the Pythagorean Theorem: (2√15)

^{2}+ (2√15)

^{2}= c

^{2}

Hence 4x15 + 4x15 = c

^{2 }or 60 + 60 = c

^{2 }

Hence 120 = c

^{2 }or c = √120 = √2x2x2x3x5= 2√30