Jan 4 Results

Next week the final meet of the year is at Friendly Hills.

Team Practice Results
Only the White Team Remembered what Mode is - the most common number in the sample.
The length and width of the pyramid increase by 20% (1.20) but the height stayed the same. Sorry Red team - I think I misled you.
FHMS GOLD 16
FHMS RED      8
FHMS WHITE  6
Heritage GOLD 22

Solutions to 3 problems:

#2 What is the intersection of x-3y=6 and y=8x-2
Since y=8x-2, let's substitute in the first equation:
x-3(8x-2)=6    Now change those minuses to plus a negative:
x+-3(8x+-2)=6  Next we'll distribute the -3 across the parentheses
x-24x+6=6 Now let's combine the x's
-23x+6=6 Subtract 6 from both sides
-23x=0 Divide both sides by -23
x=0 Now substitute 0 for x in either equation
0-3y=6
-3y=6
y=-2   so (0,-2) is the point we were looking for.
Double-check our answer by plugging (0,-2) into the 2nd equation:
-2=8(0)-2 yup!

#5. What's the volume of the New Year Ball in Times Square? It's 12' in diameter.
r= 6' Vol=4/3 pi r3 = 4/3 x 6x6x6 pi = (4/3 x 6)(6x6)pi = 8x36pi=288pi

#9. The side lengths of a right square pyramid are each increased by 20%. If the
height stays the same, by what percentage does he volume of the pyramid increase?
Two dimensions increase by 20% the third remains the same. Therefor the volume
increases by 1.20 x 1.20 = 1.44 or a 44% increase in volume