Final Math Meet of the Year at Friendly Hills on Monday Jan 11.
Heritage students will be dismissed at 2:50 to catch the bus.
Team trophies and individual medals will be awarded.
Top 6 scorers in each school will be given ribbons, but not Monday evening.
PARENTS: Pick-up at FHMS is 5:05, at HERITAGE - 5:25. Don't be late - it's cold out there!
Sunday, January 10, 2016
Monday, January 4, 2016
Jan 4 Results
Next week the final meet of the year is at Friendly Hills.
Team Practice Results
Only the White Team Remembered what Mode is - the most common number in the sample.
The length and width of the pyramid increase by 20% (1.20) but the height stayed the same. Sorry Red team - I think I misled you.
FHMS GOLD 16
FHMS RED 8
FHMS WHITE 6
Heritage GOLD 22
Solutions to 3 problems:
#2 What is the intersection of x-3y=6 and y=8x-2
Since y=8x-2, let's substitute in the first equation:
x-3(8x-2)=6 Now change those minuses to plus a negative:
x+-3(8x+-2)=6 Next we'll distribute the -3 across the parentheses
x-24x+6=6 Now let's combine the x's
-23x+6=6 Subtract 6 from both sides
-23x=0 Divide both sides by -23
x=0 Now substitute 0 for x in either equation
0-3y=6
-3y=6
y=-2 so (0,-2) is the point we were looking for.
Double-check our answer by plugging (0,-2) into the 2nd equation:
-2=8(0)-2 yup!
#5. What's the volume of the New Year Ball in Times Square? It's 12' in diameter.
r= 6' Vol=4/3 pi r3 = 4/3 x 6x6x6 pi = (4/3 x 6)(6x6)pi = 8x36pi=288pi
#9. The side lengths of a right square pyramid are each increased by 20%. If the
height stays the same, by what percentage does he volume of the pyramid increase?
Two dimensions increase by 20% the third remains the same. Therefor the volume
increases by 1.20 x 1.20 = 1.44 or a 44% increase in volume
Team Practice Results
Only the White Team Remembered what Mode is - the most common number in the sample.
The length and width of the pyramid increase by 20% (1.20) but the height stayed the same. Sorry Red team - I think I misled you.
FHMS GOLD 16
FHMS RED 8
FHMS WHITE 6
Heritage GOLD 22
Solutions to 3 problems:
#2 What is the intersection of x-3y=6 and y=8x-2
Since y=8x-2, let's substitute in the first equation:
x-3(8x-2)=6 Now change those minuses to plus a negative:
x+-3(8x+-2)=6 Next we'll distribute the -3 across the parentheses
x-24x+6=6 Now let's combine the x's
-23x+6=6 Subtract 6 from both sides
-23x=0 Divide both sides by -23
x=0 Now substitute 0 for x in either equation
0-3y=6
-3y=6
y=-2 so (0,-2) is the point we were looking for.
Double-check our answer by plugging (0,-2) into the 2nd equation:
-2=8(0)-2 yup!
#5. What's the volume of the New Year Ball in Times Square? It's 12' in diameter.
r= 6' Vol=4/3 pi r3 = 4/3 x 6x6x6 pi = (4/3 x 6)(6x6)pi = 8x36pi=288pi
#9. The side lengths of a right square pyramid are each increased by 20%. If the
height stays the same, by what percentage does he volume of the pyramid increase?
Two dimensions increase by 20% the third remains the same. Therefor the volume
increases by 1.20 x 1.20 = 1.44 or a 44% increase in volume
Monday, December 21, 2015
Team Assignments for Meet 5
Friendly Hills
Heritage
6 | Oscar Halverson | 6 | 6 | 43.3 |
6 | Cyrus Martin Risch | 0 | 4 | 28.0 |
6 | Nick Wendt | 0 | 0 | 20.7 |
6 | Nina Kessler | 2 | 1 | 20.7 |
5 | Miles Dunn | 0 | 4 | 19.3 |
5 | Claire Newmark | 16.7 | ||
6 | Lucas Lindgren | 15.3 | ||
6 | Dain Dolan | 14.7 | ||
6 | Sophia Schomer | 0 | 0 | 13.7 |
5 | Duy Houng | 12.0 | ||
5 | Will Gannon | 0 | 4 | 12.0 |
7 | Lily Pince | 0 | 2 | 10.7 |
5 | Amario Sisakda | 10.0 | ||
5 | Stella Warwick | 8.0 | ||
5 | Charles Cheesebrough | 0 | 4 | 7.3 |
6 | Victoria Dzurilla | 0 | 0 | 7.3 |
5 | Ellyanna Lee | 6.7 | ||
5 | Melissa Irwin | 0 | 2 | 5.3 |
5 | Jackson Cercioglu | 2.7 |
8 | Anthony Rocke | 42.7 | ||
8 | Ben Nickson | 0 | 6 | 25.3 |
8 | Steve Nickson | 0 | 0 | 20.0 |
5 | Aidan Mallberg | 6 | 2 | 18.7 |
6 | Kathryn Lewis | 2 | 2 | 18.0 |
5 | Emma Lawrence | 0 | 2 | 12.7 |
5 | Colten Bartlette | 7.3 | ||
5 | Ruby Lipschultz | 7.3 | ||
5 | Dia Balderramos | 2.7 | ||
5 | Maraya Lucio | 2.7 | ||
5 | Alycia Gonzales Lewis | 2.7 | ||
5 | Sophie Todaro | 1.3 |
Monday, December 14, 2015
Simultaneous Equations
1. What is the point of intersection of 2x + 3y = 7 and 5y = 3x - 1 ?
Here are 32 lessons on simultaeous equations (aka system of equations) from Kahn Academy
https://www.khanacademy.org/math/algebra/systems-of-linear-equations
Unfortunately, you probably need to start at the beginning of Kahn Academy's algebra course to really understand this.
First of all, what is our answer going to be? A point, like (0, 0).
5th grade way: We need an x and y which make both equations
true. 2x is always going to be even. 3y will be odd only if y is odd.
We want the sum to be 7, an odd number, so y must be odd.
Let's try a 1. 2x + 3 x 1 = 7. A little arithmetic tells us x=2 since
2 x 2 + 3 x 1 = 7. So our point is (2, 1) but does this solve the
other equation: 5y = 3x -1 ?
5 x 1 = 3 x 2 - 1
5 = 6 - 1 Yes! Answer: (2, 1) If it hadn't
worked on our second equation, we would have tried y = 3 or y = -1.
If these hadn't worked we'd have to use the 7th grade way.
7th grade way: We have two equations with two variables. Let's
get rid of the y's as our first step. So let's get the same number of y's
in both equations. To do this let's multiply both sides of the first
equation by 5 and the second by 3:
2x + 3y = 7 5y = 3x - 1
10x + 15y = 35 15y = 9x - 3
15y = -10x + 35
Since both expressions on the right = 15y, they must = each other!
So 9x - 3 = -10x + 35
(add 10x to each side) 19x - 3 = 35
(Now add 3 to each side) 19x = 38
(now divide both by 19) x = 2
We have x. To get y, use either of our starting equations and
put in a 2 for x.
2x + 3y = 7
2 x 2 + 3y = 7
4 + 3y = 7
(take 4 from each side) 3y = 3
(divide each side by 3) y = 1.
So x= 2 and y = 1. Our point is (2, 1)
Third way: Graph both equations on a piece of graph paper and see
where the lines cross. To graph a line, simply pick a value for x or y
and figure out the missing one.
Example: 2x + 3y = 7.
When y = 3, 2x + 9 = 7 or 2x = -2. Hence x = -1 Plot (-1, 3)
When y = -1, 2x + -3 = 7 or 2x = 10. Hence x = 5 Plot (5, -1)
Use a ruler on your graph paper to draw a straight line thru both pts.
Now do the same for the other equation. Look where they cross -
it should be at (2, 1).
Here are 32 lessons on simultaeous equations (aka system of equations) from Kahn Academy
https://www.khanacademy.org/math/algebra/systems-of-linear-equations
Unfortunately, you probably need to start at the beginning of Kahn Academy's algebra course to really understand this.
First of all, what is our answer going to be? A point, like (0, 0).
5th grade way: We need an x and y which make both equations
true. 2x is always going to be even. 3y will be odd only if y is odd.
We want the sum to be 7, an odd number, so y must be odd.
Let's try a 1. 2x + 3 x 1 = 7. A little arithmetic tells us x=2 since
2 x 2 + 3 x 1 = 7. So our point is (2, 1) but does this solve the
other equation: 5y = 3x -1 ?
5 x 1 = 3 x 2 - 1
5 = 6 - 1 Yes! Answer: (2, 1) If it hadn't
worked on our second equation, we would have tried y = 3 or y = -1.
If these hadn't worked we'd have to use the 7th grade way.
7th grade way: We have two equations with two variables. Let's
get rid of the y's as our first step. So let's get the same number of y's
in both equations. To do this let's multiply both sides of the first
equation by 5 and the second by 3:
2x + 3y = 7 5y = 3x - 1
10x + 15y = 35 15y = 9x - 3
15y = -10x + 35
Since both expressions on the right = 15y, they must = each other!
So 9x - 3 = -10x + 35
(add 10x to each side) 19x - 3 = 35
(Now add 3 to each side) 19x = 38
(now divide both by 19) x = 2
We have x. To get y, use either of our starting equations and
put in a 2 for x.
2x + 3y = 7
2 x 2 + 3y = 7
4 + 3y = 7
(take 4 from each side) 3y = 3
(divide each side by 3) y = 1.
So x= 2 and y = 1. Our point is (2, 1)
Third way: Graph both equations on a piece of graph paper and see
where the lines cross. To graph a line, simply pick a value for x or y
and figure out the missing one.
Example: 2x + 3y = 7.
When y = 3, 2x + 9 = 7 or 2x = -2. Hence x = -1 Plot (-1, 3)
When y = -1, 2x + -3 = 7 or 2x = 10. Hence x = 5 Plot (5, -1)
Use a ruler on your graph paper to draw a straight line thru both pts.
Now do the same for the other equation. Look where they cross -
it should be at (2, 1).
Scores and current ratings
HERITAGE
FRIENDLY HILLS (correction)
Some people got number 4 right, and a
few were close on some others.
I'll put solutions out once Heritage has taken the test.
I had a mistake in my formula - fixed.
Anthony Rocke | 8 | 42.7 |
Ben Nickson | 0 | 21.3 |
Steve Nickson | 20.0 | |
Kathryn Lewis | 0 | 15.3 |
Aidan Mallberg | 13.3 | |
Emma Lawrence | 0 | 11.3 |
Colten Bartlette | 0 | 7.3 |
Ruby Lipschultz | 7.3 | |
Dia Balderramos | 2.7 | |
Maraya Lucio | 0 | 2.7 |
Alycia Gonzales Lewis | 2.7 | |
Sophie Todaro | 1.3 |
Some people got number 4 right, and a
few were close on some others.
I'll put solutions out once Heritage has taken the test.
I had a mistake in my formula - fixed.
Oscar Halverson | 0 | 35.3 |
Cyrus Martin Risch | 4 | 28.7 |
Nick Wendt | 4 | 24.0 |
Miles Dunn | 4 | 20.0 |
Claire Newmark | 4 | 20.0 |
Nina Kessler | 0 | 18.7 |
Lucas Lindgren | 4 | 18.7 |
Dain Dolan | 14.7 | |
Sophia Schomer | 0 | 13.7 |
Lily Pince | 4 | 12.7 |
Duy Houng | 0 | 12.0 |
Amario Sisakda | 0 | 10.0 |
Will Gannon | 0 | 9.3 |
Stella Warwick | 0 | 8.0 |
Victoria Dzurilla | 0 | 7.3 |
Melissa Irwin | 4 | 7.3 |
Ellyanna Lee | 6.7 | |
Charles Cheesebrough | 0 | 4.7 |
Monday, December 7, 2015
Meet 4 Results
Top 10 or so in SE Metro
|
Team Name | A | B | C | Total | Year |
SPA-Gold | 62 | 66 | 40 | 168 | 620 |
SSP Maroon | 28 | 46 | 40 | 114 | 466 |
St Thomas | 34 | 36 | 34 | 104 | 462 |
SPA-Blue | 24 | 38 | 12 | 74 | 342 |
Heritage Gold | 14 | 38 | 14 | 66 | 332 |
Friendly Hills Gold | 18 | 36 | 12 | 66 | 328 |
SSP White | 12 | 30 | 10 | 52 | 298 |
Friendly Hills Red | 8 | 20 | 4 | 32 | 144 |
Trinity River Ridge | 12 | 32 | 12 | 56 | 128 |
Heritage Red | 2 | 8 | 4 | 14 | 76 |
Sunday, December 6, 2015
Team Correction
You may have noticed I forgot to sort studentss before color-coding them.
Lily will be on Red and Charles will be an alternate.
Dain will be top red and will replace anyone absent from Gold.
Ellyana will be the first alternate and will replace anyone absent from Red.
Lily will be on Red and Charles will be an alternate.
Dain will be top red and will replace anyone absent from Gold.
Ellyana will be the first alternate and will replace anyone absent from Red.
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